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Q.

10 moles of ideal gas confined to a volume of 10 L is released into atmosphere at 300K where the pressure is 1 bar. The work done by the gas is (R = 0.083 L-bar k-1 mol-1)

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a

249 L-bar

b

259 L-bar

c

239 L-bar

d

220 L-bar

answer is C.

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Detailed Solution

Initial volume = 10 LFinal volume=nRTP=10×0.083×3001=249 L ∴       ∆V=249-10=239 L ∴       W=-Pext. ∆V=1 × 239=-239 L-bar
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