Q.

0.2 moles of KOH is dissolved in a 800 ml solution. Normality of the solution is-----N

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a

0.1

b

0.5

c

0.25

d

0.4

answer is C.

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Detailed Solution

N=Number of gram equivalents×1Vl; N=Number of gram equivalents×1000Vml; Number of gram equivalents=wsoluteGEW of solute; Number of gram equivalents=Number of moles×Valency GEW=GMW or GFWvalency ; GEW of KOH=561g ; N=0.2×1×1000800=0.25 N ;
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