Q.
0.2 moles of KOH is dissolved in a 800 ml solution. Normality of the solution is-----N
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a
0.1
b
0.5
c
0.25
d
0.4
answer is C.
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Detailed Solution
N=Number of gram equivalents×1Vl; N=Number of gram equivalents×1000Vml; Number of gram equivalents=wsoluteGEW of solute; Number of gram equivalents=Number of moles×Valency GEW=GMW or GFWvalency ; GEW of KOH=561g ; N=0.2×1×1000800=0.25 N ;