$$3$$ moles of $$NH3$$ are allowed to dissociate in a $$5$$ litre vessel and the equilibrium concentration of $$N2$$ is $$0.2$$ mole $$/$$ lit. Then the total number of moles at equilibrium is

Question

$$3$$ moles of $$NH3$$      are allowed to dissociate in a $$5$$  litre vessel and the equilibrium concentration of $$N2$$      is $$0.2$$ mole $$/$$ lit. Then the  total number of moles at equilibrium is

Infinity Learn · Accepted Answer

$$2NH3$$⇌$$N2+3H2$$            $$3$$                $$0$$          $$0$$           $$2x$$              x         $$3x_$$     (3$$−$$2x)         x        $$3x$$        Given    $$x5=0.2$$ M                      $$x=$$ $$1$$ MTotal number of moles at equilibrium $$=$$                                                      $$(3$$−$$2x)+x+3x$$                                                  $$=3+1+1=5$$

3 moles of NH3 are allowed to dissociate in a 5 litre vessel and the equilibrium concentration of N2 is 0.2 mole / lit. Then the total number of moles at equilibrium is

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