Q.

Moles of Na2SO4 to be dissolved in 12 mole water to lower its vapour pressure by 10 mm Hg at a temperature at which vapour pressure of pure water is 50 mm is:

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a

1.5 mole

b

2 mole

c

1 mole

d

3 mole

answer is C.

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Detailed Solution

P∘−PP∘=∣1050=nn+12 ∴n=3
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Moles of Na2SO4 to be dissolved in 12 mole water to lower its vapour pressure by 10 mm Hg at a temperature at which vapour pressure of pure water is 50 mm is: