The moles of oxygen required to react with 6.8 gram of ammoniaNH3+O2→NO+H2O( unbalanced ) is ____?
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answer is 00000.5.
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Detailed Solution
Balanced equation is 4NH3+5O2→4NO+6H2O Therefore 4×17 gram of ammonia reacts with 5 moles of oxygen Then 6.8 gram of ammonia react with (6.8×5)/17×4 mole of oxygen =0.5