First slide

Werner's theory

Question

0.25 moles of ${PdCl}_{2} . 4 {NH}_{3}$ is treated with excess of ${AgNO}_{3}$ solution. Number of moles of $AgCl$ precipitated will be

Moderate

A

1
B

0.5
C

2
D

0.25

Solution

$[Pd {({NH}_{3})}_{4}] {Cl}_{2} ⇌ {[Pd {({NH}_{3})}_{4}]}^{+ 2} + 2 {Cl}^{-}; 1 mole 2 moles 0.25 moles 0.5 molews 0.5 {Ag}^{+} + 0.5 {Cl}^{-} \to 0.5 AgCl$

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