First slide

Concentration methods

Question

0.05 moles of Phosphorous acid is dissolved in 800 ml solution. Molarity of the solution is

Moderate

A

0.1 M
B

0.05 M
C

0.0625 M
D

0.0375 M

Solution

$M = n \times \frac{1}{V (l)}; M = n \times \frac{1000}{V (ml)}; n = \frac{w_{solute}}{GMW of solute}; M = 0.05 \times \frac{1000}{800} = 0.0625 M;$

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