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Q.

1.2 moles of SO3 are allowed to dissociate in a 2 litre vessel the reaction is 2SO3(g)⇔2SO2(g)+O2(g) and the concentration of oxygen at equilibrium is 0.1 mole per litre.  The total number of moles at equilibrium will be

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a

2

b

1.4

c

0.8

d

1.6

answer is B.

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Detailed Solution

2SO3    ⇌   2SO2  +   O2 1.22                0                0 (1.2-2x)2    2x2             x2 [oxyzen]=x2=0.1 x=0.2 nso3=1.2-0.4=0.8 nso2=2(0.2)=0.4 no2=0.2=0.2 Total moles = 0.8+0.4+0.2=1.4
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1.2 moles of SO3 are allowed to dissociate in a 2 litre vessel the reaction is 2SO3(g)⇔2SO2(g)+O2(g) and the concentration of oxygen at equilibrium is 0.1 mole per litre.  The total number of moles at equilibrium will be