1.2 moles of SO3 are allowed to dissociate in a 2 litre vessel the reaction is and the concentration of oxygen at equilibrium is 0.1 mole per litre. The total number of moles at equilibrium will be

2 moles of SO3 gives 1 mole of O2'X1' moles of SO3 gives 0.2 moles of O2Number of moles of SO3 decomposed = 0.4For every mole of O2 formed 2 moles of SO2 is formed.For every 0.2 mole of O2 formed 'X2' moles of SO2 is formed.Number of moles of SO2 formed = 0.4Total moles at equilibrium = 0.8 + 0.4 + 0.2= 1.4