The momentum of a particle which has a de Broglie wavelength of 2.5  ×  10−10m is

h=6.6  ×  10−34kg m2s−1Momentum  =hλ  using  de  Broglie  equation, momentum (mv) =hλ              =6.6  ×  10−342.5  ×  10−10= 2.64  ×  10−24 kg  m  sec−1