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a
AlCl3
b
PbCl2
c
SnCl4
d
SnCl2
answer is D.
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Detailed Solution
+4 oxidation state of Sn is more stable than +2 oxidation state. Therefore, Sn2+can be easily oxidised to Sn4+and hence SnCl2acts a reductant.SnCl2+ 2Cl → SnCl4+ 2e–