Q.

The most commonly used reducing agent is

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a

AlCl3

b

PbCl2

c

SnCl4

d

SnCl2

answer is D.

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Detailed Solution

+4 oxidation state of Sn is more stable than +2 oxidation state. Therefore, Sn2+can be easily oxidised to Sn4+and hence SnCl2acts a reductant.SnCl2+ 2Cl → SnCl4+ 2e–
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