Q.

n – Butane is treated with chlorine at250C . The percentage of 1 – chlorobutane formed is (x – 0.2) x 10. The x is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 3.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

At room temp, the relative rates of abstraction of hydrogenations are 5 : 3.8 : 1                1 - chlorobutane2 - chlorobutane =No. of10 - HNo. of 20 -H x reactivity of 10 Hreactivity of 20 H =64 x 13.8 = 615.2 % of 1 – chlorobutane = 621.2 x 100 = 28.3 % [x – 0.2] 10 = [3 – 0.2] 10 = 28 % [nearly]
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon