N2(g)+3H2(g)⇌2NH3(g)+22k.cal. The activation energy for the forward reaction is 50 k. cal. What is the activation energy for the backward reaction?

For the reaction,N2 (g)+3H2 (g)⇌2NH3 (g)+22k.cal.Given, ΔH (Change in enthalpy) = - 22K.calActivation energy of forward reaction (Ea)  = 50 K.calActivation energy of backward reaction (Eb)  =?Use the formula,ΔH=Eaf−Eab22=50−EabEab=50+22=72 K.Cal