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Q.

N2(g)+3H2(g)⇌2NH3(g)  For the reaction initially the mole ratio was 1 : 3 of N2, : H2. At equilibrium 50% of each hasreacted. If the equilibrium pressure is -Q the partial pressure of NH3, at equilibrium is

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a

P3

b

P4

c

P6

d

P8

answer is A.

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Detailed Solution

N2 + 3H2 ⇌ 2NH3 t=0 ;       a         3a            0teq. ;  (a)(1−α)   3a(1−α)    2aαGiven 50% reacted α=1/2 , n=a-aα+3a-3aα+2aα=2a(2-α)PNH3​=(mole fraction)×(total pressure)PNH3=2aα2a(2-α)P=P3
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