Q.
N2(g)+3H2(g)⇌2NH3(g) For the reaction initially the mole ratio was 1 : 3 of N2, : H2. At equilibrium 50% of each hasreacted. If the equilibrium pressure is -Q the partial pressure of NH3, at equilibrium is
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a
P3
b
P4
c
P6
d
P8
answer is A.
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Detailed Solution
N2 + 3H2 ⇌ 2NH3 t=0 ; a 3a 0teq. ; (a)(1−α) 3a(1−α) 2aαGiven 50% reacted α=1/2 , n=a-aα+3a-3aα+2aα=2a(2-α)PNH3=(mole fraction)×(total pressure)PNH3=2aα2a(2-α)P=P3
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