For N2+3H2→2NH3, rates of disappearance of N2 and H2 and rate of appearance of NH3 respectively are a, b and c, then
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a
a > b > c
b
a < c < b
c
a = b > c
d
a = b = c
answer is B.
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Detailed Solution
For every '1' mole of N2 disappearing, '3' moles of H2 disappears and '2' moles of NH3 forms.This indicates rate of disappearance N2 < Rate of appearance of NH3 < Rate of disappearance of H2a < c < b