20% of N2O4 molecules are dissociated in a sample of gas at 27ºC and 760 torr. Mixture has the density at equilibrium equal to
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
1.48 g/L
b
1.84 g/L
c
2.25 g/L
d
3.12 g/L
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Degree of decomposition, α =M-mmn-1M = MW of undissociated speciesm = MW of equilibrium mixture (observed molecular weight)n = number of particles produced by the dissociation of one moleculeN2O4(g) ⇌2NO2(g)n = 2α = 0.2T = (27 + 273)KP = 760 torr (or) 1 atmObserved molecular weight = 76.66for an ideal gas, density (d)