Q.

20% of N2O4 molecules are dissociated in a sample of gas at 27ºC and 760 torr. Mixture has the density at equilibrium equal to

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

1.48 g/L

1.84 g/L

2.25 g/L

3.12 g/L

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Degree of decomposition, α =M-mmn-1M = MW of undissociated speciesm = MW of equilibrium mixture (observed molecular weight)n = number of particles produced by the dissociation of one moleculeN2O4(g) ⇌2NO2(g)n = 2α = 0.2T = (27 + 273)KP = 760 torr (or) 1 atmObserved molecular weight = 76.66for an ideal gas, density (d)

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET