Q.

2NaZ+H2SO4(conc.)→ Na2SO4+2HZ. Z cannot be

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a

HCl

b

HF

c

HNO3

d

HI

answer is D.

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Detailed Solution

2NaI+H2SO4(conc.)→ 2HI+Na2SO42HI+H2SO4(conc.)→ I2+2H2O+SO2Conc. H2SO4   oxidizes  HI  to  I2
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