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Q.

Na2CO3 cannot be used in place of (NH4 )2CO3 for the precipitation of group V because

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a

Na⊕ interferes in the detection of group V

b

Concentration of CO32− is very low

c

Na will react with acid radicals

d

Mg will be precipitated

answer is D.

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Detailed Solution

Na2CO3 furnishes appreciable CO32 to precipitate Mg.
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