$\mathrm{Na}\left(\mathrm{s}\right)\stackrel{ }{\to }\mathrm{Na}\left(\mathrm{g}\right),\mathrm{\Delta H}=+108\mathrm{kJ}.$ $∆\mathrm{H}$ in this process cannot be called as 

• A

  Enthalpy of vaporisation

• B

  Enthalpy of sublimation

• C

  Enthalpy of atomization

• D

  All of these