Na4XeO6(aq) + xF(aq)- + yHaq+ →A(g) +z F2(g) + bH2O(l). The incorrect statement regarding balanced equation is
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a
F2 is weaker oxidizing agent than XeO6-4
b
A = XeO3
c
F- is stronger reducing agent than A(g)
d
y = 8
answer is D.
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Detailed Solution
Balanced equation is 2F-+XeO6-4+6H+→F2+XeO3+3H2OIn XeO6-4, Xe is in higest oxidation state = +8, it is stronger oxidizing agent than F2 ;SRP value of Na4XeF6/XeO3 is more positive than F2/½F- ;Direction of any redox reaction : strong oxidizing agent + strong reducing agent → weak oxidizing agent + weak reducing agent