NaCl is added to 1 litre water to such an extent that ΔTf/Kf becomes to 1500, the weight of NaCl added is

For NaCl, i = 2∴ ΔTfKf=2×Cm     ∴ ΔTf=Kf×i×Cmor, 1500=2×molalityor molality = 11000i.e.,11000moles Kg−1 wateri.e., 11000 moles per litre water=11000×58.5​ g NaCl = 0.0585 g NaCl