1.2 % NaCl solution is isotonic with 7.2% glucose solution. What will be the van't Hoff factor 'i' for NaCl ?

For NaCl, π1V1=i×n1RTπ1×1001000=1.258.5×0.0821×T×i            ....(i)For glucose , π2V=n2RTπ2×1001000=7.2180×0.0821×T         ......(ii)                                         (∵ for glucose i=1 ) ∵aCl and glucose solutions are isotonic.∴                  π1=π2⇒      i=7.2180×58.51.2=1.95≈2