$$NaClO3$$ is used, even in spacecrafts, to produce $$O2$$. The daily consumption of pure $$O2$$ by a person is $$492$$ L at $$1$$ atm, $$300$$ K. How much amount of $$NaClO3$$, in grams, is required to produce $$O2$$ for the daily consumption of a person at $$1$$ atm, $$300$$ K?$$NaClO3$$ (s) $$+$$ $$Fe(s)$$ → $$O2$$ (g) $$+$$ NaCl (s) $$+$$ FeO $$(s)R$$ $$=$$ $$0.082$$ L atm $$mol-1$$ $$K-1$$

Question

$$NaClO3$$ is used, even in spacecrafts, to produce $$O2$$. The daily consumption of pure $$O2$$ by a person is $$492$$ L at $$1$$ atm, $$300$$ K. How much amount of $$NaClO3$$, in grams, is required to produce $$O2$$ for the daily consumption of a person at $$1$$ atm, $$300$$ K?$$NaClO3$$ (s) $$+$$ $$Fe(s)$$ → $$O2$$ (g) $$+$$ NaCl (s) $$+$$ FeO $$(s)R$$ $$=$$ $$0.082$$ L atm $$mol-1$$ $$K-1$$

Infinity Learn · Accepted Answer

$$NaClO3+Fe$$→$$O2+NaCl+FeO$$ $$x106.5=1$$×$$492300$$×$$0.082x=2130gms$$

Gaseous state

Unlock the full solution & master the concept.

${NaClO}_{3} + Fe \to O_{2} + NaCl + FeO \frac{x}{106.5} = \frac{1 \times 492}{300 \times 0.082}$
x=2130gms

Ready to Test Your Skills?

speak to our academic counsellor

free study material

Gaseous state

Unlock the full solution & master the concept.

NaClO3+Fe→O2+NaCl+FeO x106.5=1×492300×0.082x=2130gms

Ready to Test Your Skills?

speak to our academic counsellor

free study material

${NaClO}_{3} + Fe \to O_{2} + NaCl + FeO \frac{x}{106.5} = \frac{1 \times 492}{300 \times 0.082}$
x=2130gms