NaClO3 is used, even in spacecrafts, to produce O2. The daily consumption of pure O2 by a person is 492 L at 1 atm, 300 K. How much amount of NaClO3, in grams, is required to produce O2 for the daily consumption of a person at 1 atm, 300 K?NaClO3 (s) + Fe(s) → O2 (g) + NaCl (s) + FeO (s)R = 0.082 L atm mol-1 K-1

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answer is 2130.

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Detailed Solution

NaClO3+Fe→O2+NaCl+FeO x106.5=1×492300×0.082x=2130gms

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