To neutralize completely 20 mL of 0.1 M aqueous solution of phosphorus H3PO3 acid the volume of 0.1 M aqueous KOH solution required is

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60 mL

20 mL

40 mL

10 mL

answer is C.

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Detailed Solution

Meq. Of H3PO3=Meq. of KOHN1V1= N2V2 N1=N H3PO3=M×Basicity=0.1×2 ; N2=NNaOH=M×Acidity=0.1×1V1=20ml ; V2=V=?∴ 20 × 0.1 × 2=V × 0.1 V=40 mLa

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