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Q.

n-factor of KMnO4 as an oxidizing agent in neutral medium is ‘n1’ and n-factor of K2Cr2O7 as an oxidizing agent in acidic medium is ‘n2’. Product of n1 and n2 is equal to

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a

18

b

6

c

30

d

15

answer is A.

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Detailed Solution

M+7nO4-→M+4nO2....neutal medium....n-factor=3 ; C+6r2O72-→Cr3+....acidic medium....n-factor=6 ; n1×n2=3×6=18 ;
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