Nickel (Z = 28) combines with a uninegative monodentate ligand X- to form a paramagnetic complex [NiX4]2-. The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively:
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a
One, tetrahedral
b
Two, tetrahedral
c
One, square planar
d
Two, square planar
answer is B.
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Detailed Solution
If X- is weak field ligand (say Cl-) then NiCl42− is tetrahedral (sp3) with two unpaired electrons. If X- is strong field ligand (say CN-), then NiCN42− is square planar (dsp2) with no unpaired electron. Also given NiX42− is paramagnetic.
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Nickel (Z = 28) combines with a uninegative monodentate ligand X- to form a paramagnetic complex [NiX4]2-. The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively: