NO3−+I2→H+NO2+IO3−; In the balanced equation, the number of H2O and H+ ions are

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4H2O on LHS and 8H+ on RHS

8H+ on LHS and 4H2O on RHS

2H2O on LHS and 8H+ on RHS

4H+ on LHS and 2H2O on RHS

answer is B.

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Detailed Solution

NO3−→NO2; I2→2IO3−NO3−→NO2+H2O; I2+6H2O→2IO3−NO3−+2H+→NO2+H2O; I2+6H2O→2IO3−+12H+NO3−+2H++e−→NO2+H2O;×10 I2+6H2O→2IO3−+12H++10e−

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