No work is done on the system but q amount of heat is taken out from the system and given to the surroundings. Which of the following is correct?
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a
∆U=wext; wall is adiabatic.
b
∆U=-q; wall is thermally conducting.
c
∆U=q-w; the system is a closed system.
d
∆U=-wext; wall is conducting thermally.
answer is B.
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Detailed Solution
Because heat is taken out of the system, q is -ve. Since, no work is related with the system, w = 0. Hence∆U=q+w=-q+0∆U=-qThe wall is thermally conducting.