The normality of a solution that results from mixing 4 g of NaOH, 500 mL of I M HCl, and 10.0 mL of H2O2 (specific gravity 1.1, 49% H2SO4 by weight) is(The total volume of solution was made to 1 L with water)

4g of NaOH=4/40=0.1mole=100mmol≡100mEqHCl=500×1=500mEqN of H2SO4=W2×1000Ew2×Vsol ( in mL) or =% by weight ×10×dEw2 =49×10×1.149=11NmEq of H2SO4=11N×10.00mL=110mEq  Total acid =110+500=610 m Eq NaOH=100 m Eq  Acid left =610−100=510 m Eq  Total volume =1000 mL  Normality of solution =mEqmL=5101000=0.51N