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Q.

In the nuclear reaction  92U232→90Th228+2He4, (Given: m(U) = 232.038u, m(Th) = 228.0.29 u and m (He) = 4.003 u), the ratio of speed of α-particle and speed of light is about

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a

0.25

b

0.036

c

0.005

d

0.018

answer is C.

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Detailed Solution

Δm=m(Th)+m(He)−m(U)=(228.029+4.003−232.038)u = - 0.006 uHence 12m(He)u2=|(Δm)|c2 or (u/c)=21(Δm)m or (u/c)=(2×0.006/4.003)1/2=0.005
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