Q.

The number of atoms in 0.1 mol of a triatomic gas is (NA=6.02×1023mol−1)

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a

1.800×1022

b

6.026×1022

c

1.806×1023

d

3.600×1023

answer is C.

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Detailed Solution

No. of. Atoms = 0.1×6.02×1023×30.3×6.02×1023=1.806×1023
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