Q.
The number of atoms in 0.1 mole of a triatomic gas isNA=6.02×1023mol−1
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a
1.800×1022
b
6.026×1022
c
1.806×102.3
d
3.600×1023
answer is C.
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Detailed Solution
No. of atoms = No. of molecules x atomicity=0.1NA×3=0.1×6.02×1023×3=1.806×1023.
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