Q.

The number of atoms present in one mole of an element is equal to Avogadro number. which of the following element contains the greatest number of atoms?

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a

4 g He

b

46 g Na

c

0.40 g Ca

d

12 g He

answer is D.

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Detailed Solution

12 g of He (3 moles of He) contains the greatest number of atoms4 g of He=6.023×1023 atomsof He12 g of He contains =6.023×10234×12=18.069×1023 atoms of He.
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