Q.
The number of atoms present in one mole of an element is equal to Avogadro number. which of the following element contains the greatest number of atoms?
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a
4 g He
b
46 g Na
c
0.40 g Ca
d
12 g He
answer is D.
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Detailed Solution
12 g of He (3 moles of He) contains the greatest number of atoms4 g of He=6.023×1023 atomsof He12 g of He contains =6.023×10234×12=18.069×1023 atoms of He.
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