The number of chlorine atoms in 20 mL of chlorine gas at STP is ______1021. (Round off to the Nearest Integer)(Assume chlorine is an ideal gas at STP, R=0.083L bar mol−1K−1,NA=6.023×1023 )

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Detailed Solution

Total number of atoms = nNA×Atomicity=PVRT×6.023×1023×2=1×0.020.083×273×6.023×1023×2 ≃1×1021

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