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Question

The number of correct options is

 (a) I >Br>Cl>F (polarisability) 

 (b) Li>Na>K>Rb (polarisation power) 

 (c) H2O>H2S>H2Se>H2 Te (order of b.pt.) 

 (d) H2<H2 (order of stability) 

Moderate
Solution

(a), (b) and (d) are correct options.

(a) I>Br>Cl>F (Polarisability).

According to Fajan's rule, large anion is more polarisable.

(b) Li>Na>K>Rb (Polarisation power).

According to Fajan's rule, small cation is more polarisable.

(c) Wrong.

      Boiling point order is

(d) Both H2 and H2 have same bond order of 0.5.
     H2 is more stable than H2, since H2contains
     one e- in bonding orbitals whereas H2 contains
     one e- in antibonding orbitals.


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