Organic molecular structures and naming
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Number of diastereomer of the given compound is:
Number of chiral C-atoms = 3, (n = 3, odd number and terminal groups are same).
Number of total isomers :.
Number of optically inactive (meso forms)
Number of optically active forms = 4 - 1 = 3
Hence number of diastereomers = 3.
II and III are same. Check after rotating to 180°
.'. Diastereomer pairs are
1. I and II or III 2. I and IV
3. II or III and IV
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