First slide

Faraday's Laws

Question

The number of electorns delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60 × 10^–19 C)

Moderate

A

6 × 10²³
B

6 × 10²⁰
C

3.75 × 10²⁰
D

7.48 × 10²³

Solution

Total number of coulombs passed = i x t = 1 x 60 = 60
$No . of Electrons transformed = \frac{Total coulombs passed}{Charge on electron in Coulomb} = \frac{60}{1.6 \times 10^{- 19}} = 3.75 \times 10^{- 20}$

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