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The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is ?(charge on electron = 1.60×10-19C)

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answer is 3.

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Detailed Solution

Q=I×tQ=1×60=60C Now, 1.60×10-19C≡1 electron ∴60C≡601.6×10-19=37.5×1019=3.75×1020 electrons

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