First slide

Faraday's Laws

Question

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is ?
(charge on electron = $1.60 \times 10^{- 19} C$ )

Moderate

Solution

$Q = I \times t$
$Q = 1 \times 60 = 60 C$
${Now, 1.60×10}^{- 19} C \equiv 1 electron$
$∴ 60 C \equiv \frac{60}{1.6 \times 10^{- 19}} = 37.5 \times 10^{19} = 3.75 \times 10^{20} electrons$

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