First slide
Faraday's Laws
Question

The number of electrons involved in the electro deposition of 63.5 g. of Cu from a solution of CuSO4 is

Easy
Solution

1 F deposits 1 eq of Cu from its salt solution.

1 F = charge carried by 6.02 x 1023 electrons.

1 eq of Cu = 31.75 gm

For the electro deposition of 31.75 gm of Cu =6.02 x 1023 electrons.

For the electro deposition of 63.5gm of Cu =\frac{{63.5 \times 6.02 \times {{10}^{23}}}}{{31.75}} = 12.04 \times {10^{23}}

 

 

 

 


                                                                                          

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