The number of electrons in sulphur atom having n+l=3 are :

Sulphur ( Z = 16) has electronic configuration =1s22s22p63s23p4⋅n+l=3 is for:2p because in this case, n=2,l=1. So, n+l=2+1=3 Number of electrons in 2p sub-shell are 6.3s because in this case,n=3,l=0. So, n+l=3+0=3 Number of electrons in 3s sub-shell are 2 Hence:Total number of electrons= 6 + 2 = 8. So, true answer is (a)