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Q.

The number of milliequivalents present in 25 mL of 0.2N Mg(OH)2 are

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a

0.5

b

0.25

c

5.0

d

10.0

answer is C.

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Detailed Solution

Mg(OH)2⇌Mg2++2OH−M. eq. of Mg(OH)2= Volume in mL× normality = 25 X 0.2 = 5.0

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