Q.
The number of molecules of CO2 present in 44 g of CO2 is
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a
3×1010
b
3×1023
c
12×1023
d
6.0×1023
answer is D.
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Detailed Solution
Weight of CO2 = 44Mol. wt. of CO2 = 44No. of molecule= wt. of CO2 mol. wt. of CO2×6.02×1023=4444×6.02×1023=6.02×1023
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