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Q.

The number of molecules of CO2 present in 44 g of CO2 is

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a

3×1010

b

3×1023

c

12×1023

d

6.0×1023

answer is D.

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Detailed Solution

Weight of CO2 = 44Mol. wt. of CO2 = 44No. of molecule= wt. of CO2 mol. wt. of CO2×6.02×1023=4444×6.02×1023=6.02×1023

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