Q.
The number of moles of AgCl obtained when excess of AgNO3 is added to one mole of CoCl3.4NH3
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a
1
b
2
c
3
d
4
answer is A.
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Detailed Solution
CoCl3.4NH3⇒CoNH34Cl2ClCONH34Cl2Cl+AgNO3excess of →CONH34Cl2NO3+AgCl↓1 mole of AgCl
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