Q.

The number of moles of AgCl obtained when excess of AgNO3 is added to one mole of CoCl3.4NH3

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a

1

b

2

c

3

d

4

answer is A.

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Detailed Solution

CoCl3.4NH3⇒CoNH34Cl2ClCONH34Cl2Cl+AgNO3excess of →CONH34Cl2NO3+AgCl↓1 mole of AgCl
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