Number of moles of MnO4-  required to oxidize one mole of ferrous oxalate completely in acidic medium will be

In acidic medium MnO4- oxidises ferrous oxalate as follows :2MnO4-+5C2O4-2+16H+→2Mn2++10CO2+8H2O∵ 5 moles of oxalate ions are oxidised by 2 moles of MnO4-.∴ 1 mole of oxalate ion is oxidised by=25mole ofMnO4-=0.4moles