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Number of moles of NH4OH required to coagulate 1 mole of Fe(OH)3 / Fe3+ sol are
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a
4
b
2
c
3
d
1
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Correct option is C
3NH4OH+[Fe(OH)3]Fe+3→Fe(OH)3 Moles of NH4OH required to coagulate [Fe(OH)3]Fe+3ion = 3
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