Q.

Number of moles of NH4OH required to coagulate 1 mole of Fe(OH)3 / Fe3+ sol are

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By Expert Faculty of Sri Chaitanya

a

4

b

2

c

3

d

1

answer is 3.

(Detailed Solution Below)

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Detailed Solution

3NH4OH+[Fe(OH)3]Fe+3→Fe(OH)3  Moles of NH4OH  required to coagulate   [Fe(OH)3]Fe+3ion = 3
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