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Q.

The number of moles of oxalate ions oxidized by one mole of MnO4- ion is

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a

1/5

b

2/5

c

5/2

d

5

answer is C.

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Detailed Solution

The balanced equation is5C2O42- + 16H+ + 2MnO4- → 10CO2 + 8H2O + 2Mn2+ Now 2 moles of MnO4- requires 5moles of C2O4-2 ∴ 1 mol of MnO4- → 52 mol

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