Q.

The number of moles of and separately required to oxidise one mole of FeC2O4 each in acidic medium respectively

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answer is 4.

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Detailed Solution

n-factor for MnO4- = 5 (MnO4- → Mn+2)n-factor for Cr2O7-2 = 6 (Cr2O7-2 → Cr+3)n-factor for FeC2O4 = 3 (Fe+2 →Fe+3 & C2O4-2 →CO2) n-factorCriss cross  3moles of  MnO4- oxidizes 5 mole of FeC2O4'X' mole of MnO4- oxidizes 1mole of FeC2O4  n-factorCriss - cross method3 moles of Cr2O7-2 oxidizes 6 mole of FeC2O4'X2' mole of Cr2O7-2 oxidizes 1 mole of FeC2O4
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The number of moles of and separately required to oxidise one mole of FeC2O4 each in acidic medium respectively