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Q.

The number of oxalic acid molecules in 100 ml of 0.02 N oxalic acid is

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a

6.023  ×  1020

b

6.023  ×  1021

c

6.023  ×  1022

d

6.023  ×  1023

answer is A.

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Detailed Solution

Normality=Molarity × Valence factor∴  Molarity =NormalityValence factorValence factor  for  oxalic  acid=mol.  wt.  of  oxalic  acidEq.  wt.  of  oxalic  acid=mol.  wt.  of  oxalic  acidmol.  wt.  of  oxalic  acid×2=2As  basicity  of  oxalic  acid  is 2 & E=Mol.wt.2Molarity=202 = 0.01Number  of  millimoles=0.01 × 100Number  of moles  =  0.001∴   Number  of  oxalic  acid  molecules=0.001 ×  6.023 × 1023                                                    =  6.023 × 1020
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