Electromagnetic radiation and spectra

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By Expert Faculty of Sri Chaitanya
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Question

The number of photons emitted by a monochromatic (single frequency) infrared range finder of power 1 mW and wavelength of 1000 nm, in 0.1 second is x×1013. The value of x is _____________. (Nearest integer)

(h = 6.63 ×× 1034 Js, c = 3.00 ×× 108 ms1)

Moderate
Solution

Energy emitted in 0.1 sec. = 0.1 sec. × 10−3J/s = 10−4 J

If 'n' photons of λ = 1000 nm are emitted, then 10−4 =  nhcλ

104=n×6.63×1034×3×1081000×109

 n = 5.02 × 1014 = 50.2 × 1013

 50 (nearest integer)


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