The number of photons emitted by a monochromatic (single frequency) infrared range finder of power 1 mW and wavelength of 1000 nm, in 0.1 second is x×1013. The value of x is _____________. (Nearest integer)
(h = 6.63 × 10−34 Js, c = 3.00 × 108 ms−1)
Energy emitted in 0.1 sec. = 0.1 sec. × 10−3J/s = 10−4 J
If 'n' photons of = 1000 nm are emitted, then 10−4 =
n = 5.02 × 1014 = 50.2 × 1013
50 (nearest integer)
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