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Questions  

The number of pie bonds formed during the dehydrohalogenation of one mole 1,1,6,6–tetrabromohexane with 6 moles of sodamide?

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By Expert Faculty of Sri Chaitanya
a
2
b
3
c
4
d
zero

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detailed solution

Correct option is C

dehydrohalogenation of one mole 1,1,6,6–tetrabromoHexane with 6 moles of sodamide will give hexa–1,5–diyne. It contains four pie-bonds.


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