First slide

Alkynes

Question

The number of pie bonds formed during the dehydrohalogenation of one mole 1,1,6,6–tetrabromohexane with 6 moles of sodamide?

Moderate

A

2
B

3
C

4
D

zero

Solution

dehydrohalogenation of one mole 1,1,6,6–tetrabromoHexane with 6 moles of sodamide will give hexa–1,5–diyne. It contains four pie-bonds.

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